Within the Java language, the only way to create an object is by calling its constructor, be it explicitly or implicitly. Using reflection results in a call to the constructor method, deserialization uses reflection to …

May 6, 2012 · Create new object using reflection? Asked 13 years, 7 months ago Modified 9 years ago Viewed 66k times

In java 6 org.json.JSONArray contains the put method and in java 7 javax.json contains the add method. An example of this using the builder pattern in java 7 looks something like this:

Nov 21, 2013 · How to create JSON Object using String? Asked 12 years ago Modified 2 years, 6 months ago Viewed 673k times

Jun 24, 2010 · 235 Starting from Java 9, there is a new utility method allowing to create an immutable entry which is Map#entry(Object, Object). Here is a simple example:

Sep 17, 2008 · 7 Java unfortunatly does not allow what you want to do. See the official workaround : You cannot create an instance of a type parameter. For example, the following code causes a …

Oct 24, 2012 · So, when you create an instance from main method, the constructor is invoked to initialize the state of your instance, and then when the constructor returns, the next statement of your …

Is there a way to create an instance of a particular class given the class name (dynamic) and pass parameters to its constructor. Something like: Object object = createInstance("mypackage.MyClass","

How can I create a java.nio.file.Path object from a String object in Java 7? I.e.

Why do you need to create a BLOB object ? Or do you want to read the BLOB data from the DB ?